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Evaluate: $(6-1 - 8-1)-1 + (2-1-3-1)-1$.
Given:
$(6-1 - 8-1)-1 + (2-1-3-1)-1$.
To do:
We have to evaluate $(6-1 - 8-1)-1 + (2-1-3-1)-1$.
Solution:
$(6-1 - 8-1)-1 + (2-1-3-1)-1=[6-(1+8+1)]+[2-(1+3+1)]-1$
$=(6-10)+(2-5)-1$
$=-4+(-3)-1$
$=-(4+3+1)$
$=-8$
Therefore,
$(6-1 - 8-1)-1 + (2-1-3-1)-1=-8$.
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