If $x=1,\ y=2$ and $z=5$, find the value of $3x-2y+4z$.
Given: If $x=1,\ y=2$ and $z=5$.
To do: To find the value of $3x-2y+4z$.
Solution:
$3x-2y+4z$
$=3(1)-2(2)+4(5)$
$=3-4+20$
$=19$
Thus, the value of $3x-2y+4z=19$.
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