f $x=1,\ y=2$ and $z=5$, find the value of $2x^{2}-3y^{2}+z^{2}$.

Given: $x=1,\ y=2$ and $z=5$.

To do: To find the value of $2x^{2}-3y^{2}+z^{2}$.

Solution:

$2x^{2}-3y^{2}+z^{2}$

$=2(1)^2-3(2)^2+5^2$

$=2-12+25$

$=27-12$

$=15$

Thus, the value of $2x^{2}-3y^{2}+z^{2}=15$.

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Updated on: 10-Oct-2022

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