Instruction type CMP R in 8085 Microprocessor


In 8085 Instruction set, CMP is a mnemonic that stands for “CoMPareAccumulator” and hereR stands for any of the following registers, or memory location M pointed by HL pair.

R = A, B, C, D, E, H, L, or M

This instruction is used to compare contents of the Accumulator with given register R. The result of compare operation will be stored in the Temp register. Temp is not a GPR (General Purpose Register) but an internal register that is not accessible to the programmer. Actually R register’s content will get subtracted from Accumulators content and difference value will be stored on the Temp register. As R can have any of the eight values, there are eight opcodes for this type of instruction. It occupies only 1-Byte in memory.

Mnemonics, Operand Opcode(in HEX) Bytes
CMP A BF 1
CMP B B8 1
CMP C B9 1
CMP D BA 1
CMP E BB 1
CMP H BC 1
CMP L BD 1
CMP M BD 1

Let us consider one sample instruction CMP E falling in this category.As It is a 1-Byte instruction so during execution of this instruction it will occupy only a single Byte in memory. The result of execution of this instruction has been depicted with following set of examples −

Example 1

Before After

(A)

50H 50H

(E)

70H 70H

(Temp)

Any value E0H

(F)

Any value Cy=1,AC=0,S=1,P=0,Z=0

Example 2

Before After

(A)

70H 70H

(E)

50H 50H

(Temp)

Any value 20H

(F)

Any value Cy=0,AC=0,S=0,P=0,Z=0

Example 3

Before After

(A)

50H 50H

(E)

50H 50H

(Temp)

Any value 00H

(F)

Any value Cy=0,AC=0,S=0,P=1,Z=1

Address Hex Codes Mnemonic Comment
2004 BB CMP E Temp = Register A - Register E

The timing diagram against this instruction CMP E execution is as follows −

CMP E

Summary − So this instruction CMP E requires 1-Byte, 1-Machine Cycle (Opcode Fetch) and 4 T-States for execution as shown in the timing diagram.

karthikeya Boyini
karthikeya Boyini

I love programming (: That's all I know

Updated on: 30-Jul-2019

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