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Instruction type ANA R in 8085 Microprocessor
In 8085 Instruction set, ANA is a mnemonic, which stands for “ANd Accumulator” and “R” stands for any one of the following registers, or memory location M pointed by HL pair.
R = A, B, C, D, E, H, L, or M
This instruction is used to AND contents of R with Accumulator’s content. The result thus produced for this AND operation will be stored back in to the Accumulator over writing its previous content. As R can have any of the eight values, there are eight opcodes for this type of instruction. It occupies only 1-Byte in memory.
Mnemonics, Operand | Opcode(in HEX) | Bytes |
---|---|---|
ANA A | A7 | 1 |
ANA B | A0 | 1 |
ANA C | A1 | 1 |
ANA D | A2 | 1 |
ANA E | A3 | 1 |
ANA H | A4 | 1 |
ANA L | A5 | 1 |
ANA M | A6 | 1 |
Let us consider ANA E is an example instruction of this type. As it is a 1-Byte instruction so in memory only a single Byte will get allocated for it during execution. Let us consider the initial content of Accumulator is ABH and register E is CDH. So after The result of execution of this instruction has been depicted in the following tracing table −
Before | After | |
---|---|---|
(E) |
CDH | CDH |
(A) |
ABH | 89H |
(F) |
Any values | Cy=0,AC=1,Z=0,P=0,S=1 |
The internal calculation will be done as shown below −
(A) ABH ---> 1010 1011 (d8) CDH ---> 1100 1101 --------- ANA E ---> 1000 1001 (89H)
Address | Hex Codes | Mnemonic | Comment |
---|---|---|---|
2004 | A3 | ANA E | A = A and E |
The timing diagram against this instruction ANA E execution is as follows −
Summary − So this instruction ANA E requires 1-Byte, 1-Machine Cycle (Opcode Fetch) and 4 T-States for execution as shown in the timing diagram.