Three-phase Induction Motor - Winding EMFs (Stator EMF and Rotor EMF)



Let suffixes "s" and "r" be used for stator and rotor quantities, respectively. Then,

Vs = Stator applied voltage per phase

Ns = Number of stator winding turns in series per phase

Nr = Number of rotor winding turns in series per phase

= Resultant flux in air gap

Es = Stator induced EMF per phase

Er0 = EMF induced in the rotor per phase when the rotor is at standstill

Ers = EMF induced in the rotor per phase when the rotor is rotating at a slip s

Rs = Resistance of stator winding per phase

Rr = Resistance of rotor winding per phase

Lr0 = Rotor inductance per phase at standstill due to leakage flux

Xr0 = Leakage reactance of the rotor winding per phase when the rotor is at standstill

fs = Supply frequency

fr = Frequency of the induced EMF in the rotor at a slip s

Xrs = Leakage reactance of rotor winding per phase when the rotor is rotating at a slip s

kds = Distribution factor of stator winding

kdr = Distribution factor of rotor winding

kcs = Coil span factor of stator winding

kcr = Coil span factor of rotor winding

Then, the induced EMF in the stator winding per phase is given by,

$$\mathrm{E_{s} \:=\: 4.44 \: k_{cs} \: k_{ds} \: f_{s} \: \varphi \: N_{s}\:\: \dotso \: (1)}$$

The induced EMF per phase in the rotor when the rotor is at standstill is given by,

$$\mathrm{E_{r0} \:=\: 4.44 \: k_{cr} \: k_{dr} \: f_{s} \: \varphi \: N_{r}\:\: \dotso \: (2)}$$

The induced EMF per phase in the rotor when the rotor is rotating at a slip 's' is given by,

$$\mathrm{E_{rs} \:=\: s E_{r0}}$$

$$\mathrm{\therefore \: E_{rs} \:=\: 4.44 \:k_{cr} \:k_{dr} \: s \: f_{s} \: \varphi \: N_{r} \:\: \dotso \: (3)}$$

Now, let,

  • kcs kds = kw = Winding factor of stator
  • kcr kdr = kwr = Winding factor of rotor

Then,

$$\mathrm{E_{s} \:=\: 4.44 \:k_{ws} \: f_{s} \: \varphi \: N_{s} \:\: \dotso \: (4)}$$

And

$$\mathrm{E_{rs} \:=\: 4.44 \: k_{wr} \: s f_{s} \:\varphi\: N_{r} \:\: \dotso \: (5)}$$

Now, taking the ratio of eqns. (4) and (5), we get,

$$\mathrm{\frac{E_{s}}{E_{rs}} \:=\: \frac{k_{ws} \: N_{s}}{k_{wr} \: N_{r}} \:=\: \frac{N_{es}}{N_{er}} \:=\: a_{eff} \:\: \dotso \: (6)}$$

Where, Nes and Ner are known as effective stator and rotor turns per phase, respectively.

And aeff is known as effective turns ratio of an induction motor.

Also,

$$\mathrm{\frac{I′_r}{I_{r}} \:=\: \frac{N_{er}}{N_{es}} \:=\: \frac{1}{a_{eff}} \:\: \dotso \: (7)}$$

From equation (6), it is clear that the ratio between stator and rotor EMFs is constant at standstill. This ratio depends upon the turns ratio modified by the distribution and coil span factors of the windings. Hence, an induction motor behaves like a transformer. The number of slots in stator and rotor may be different, thus, the factors for the stator and rotor windings are not the same.

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