# Construct Binary Tree from Preorder and Postorder Traversal in Python

PythonServer Side ProgrammingProgramming

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Suppose we have two traversal sequences Preorder and Postorder, we have to generate the binary tree from these two sequences. So if the sequences are [1,2,4,5,3,6,7], [4,5,2,6,7,3,1], then the output will be To solve this, we will follow these steps −

• ans := make a tree node by taking value pre, stack := empty stack, and insert ans
• i := 1 and j := 0
• while i < length of pre and j < length of post
• if stack top value = post[j], then increase j by 1, pop from stack, and go for next iteration
• node := make a tree node with value pre[i]
• if left part of stack top node is empty, then set left of stack top node as node, otherwise set right of stack top node as node
• insert node into stack
• increase i by 1
• return ans

Let us see the following implementation to get better understanding −

## Example

class TreeNode:
def __init__(self, data, left = None, right = None):
self.data = data
self.left = left
self.right = right
def height(root):
if root is None:
return 0
else :
# Compute the height of left and right subtree
l_height = height(root.left)
r_height = height(root.right)
#Find the greater one, and return it
if l_height > r_height :
return l_height+1
else:
return r_height+1
def print_given_level(root, level):
if root is None:
return
if level == 1:
print(root.data,end = ',')
elif level > 1 :
print_given_level(root.left , level-1)
print_given_level(root.right , level-1)
def level_order(root):
print('[', end = '')
h = height(root)
for i in range(1, h+1):
print_given_level(root, i)
print(']')
class Solution(object):
def constructFromPrePost(self, pre, post):
"""
:type pre: List[int]
:type post: List[int]
:rtype: TreeNode
"""
ans = TreeNode(pre)
stack = [ans]
i = 1
j = 0
while i < len(pre) and j < len(post):
if stack[-1].data == post[j]:
j+=1
stack.pop(-1)
continue
node = TreeNode(pre[i])
if not stack[-1].left:
stack[-1].left = node
else:
stack[-1].right = node
stack.append(node)
i+=1
return ans
ob = Solution()
pre = [1,2,4,5,3,6,7]
post = [4,5,2,6,7,3,1]
tree = ob.constructFromPrePost(pre, post)
level_order(tree)

## Input

[1,2,4,5,3,6,7]
[4,5,2,6,7,3,1]
pre = [1,2,4,5,3,6,7]
post = [4,5,2,6,7,3,1]

## Output

[1,2,3,4,5,6,7,]