Construct Binary Tree from Preorder and Inorder Traversal in Python

Suppose we have the inorder and preorder traversal sequence of a binary tree. We have to generate the tree from these sequences. So if the preorder and inorder sequences are [3,9,20,15,7] and [9,3,15,20,7], then the tree will be −

Let us see the steps −

  • Suppose the method is called buildTree with preorder and inorder lists
  • root := first node from the preorder, and delete first node from preorder
  • root_index := index of root.val from the inorder list
  • left or root := buildTree(preorder, subset of inorder from 0 to root_index)
  • right or root := buildTree(preorder, subset of inorder from root_index + 1 to end)

Let us see the following implementation to get better understanding −


 Live Demo

class TreeNode:
   def __init__(self, data, left = None, right = None): = data
      self.left = left
      self.right = right
def print_tree(root):
   #print using inorder traversal
   if root is not None:
      print(, end = ',')
class Solution(object):
   def buildTree(self, preorder, inorder):
      if inorder:
         root = TreeNode(preorder.pop(0))
         root_index = inorder.index(
         root.left = self.buildTree(preorder,inorder[:root_index])
         root.right = self.buildTree(preorder,inorder[root_index+1:])
         return root
ob1 = Solution()
print_tree(ob1.buildTree([3,9,20,15,7], [9,3,15,20,7]))




9, 3, 15, 20, 7,

Updated on: 04-May-2020


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