# The larger of two supplementary angles exceeds the smaller by 18Â°. Find the angles.

**Given:**

The larger of two supplementary angles exceeds the smaller by 18°.

**To do:**

We have to find the angles.

**Solution:**

Let the larger angle be x.

This implies,

Smaller angle $= x-18°$

We know that,

Supplementary angles add up to 180°.

Therefore,

$x + x -18° = 180°$

$2x - 18° = 180°$

$2x = 180° + 18°

$2x = 198°$

$x = \frac{198°}{2}$

$x = 99°$

$x - 18° = 99° - 18° = 81°$

**
**

**The larger angle is 99° and the s****maller angle is 81°.**

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