Two supplementary angles differ by $48^o$. Find the angles.

Given:

Two supplementary angles differ by $48^o$. 

To do:

We have to find the measure of the angles.

Solution:

Two angles are said to be supplementary if the sum of their measures is $180^o$.

Let the required angles be $x$ and $x+48^o$.

Therefore,

$x+(x+48^o)=180^o$

$2x=180^o-48^o$

$x=\frac{132^o}{2}$

$x=66^o$

This implies,

$x+48^o=66^o+48^o=114^o$

The measures of the required angles are $66^o$ and $114^o$. 

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

67 Views

Kickstart Your Career

Get certified by completing the course

Get Started