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# Divide 72 into two parts, so that the larger part exceeds the smaller part by 12. Find both the parts.

**Given :**

Divide 72 into two parts and the larger part exceeds the smaller part by 12

**
**

**To find :**

We have to find both the parts.

**
**

**Solution :**

Let the two numbers be x and y.

The larger part exceeds the smaller part by 12.

$x = y+12$

$x+y = 72$

$y+12+y =72$

$2y = 72-12$

$2y = 60$

$y = \frac{60}{2}$

$y = 30$

$x = 30+12$

$x = 42$

**
**

**The parts are 42 and 30.**

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