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Among two supplementary angles, the measure of the larger angle is 44o more than the measure of the smaller. Find their measures.
Given: Among two supplementary angles, the measure of the larger angle Is $44^{o}$ more than the measure of the smaller.
To find: Here we have to find the measure of the angles.
Solution:
Let the smaller angle be $=\ a$
So, the larger angle be $=\ a\ +\ 44^{o}$
Now,
Two angles are supplementary to each other when their sum is $180^{o}$. Therefore,
$a\ +\ (a\ +\ 44^{o})\ =\ 180^{o}$
$2a\ =\ 180^{o}\ -\ 44^{o}$
$2a\ =\ 136^{o}$
$a\ =\ \frac{136^{o}}{2}$
$a\ =\ 68^{o}$
So,
The smaller angle be $=\ a\ =\ \mathbf{68^{o}}$
And,
The larger angle be $=\ a\ +\ 44^{o}\ =\ 68^{o}\ +\ 44^{o}\ =\ \mathbf{112^{o}}$
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