- Trending Categories
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
In a simultaneous throw of a pair of dice, find the probability of getting a sum less than 7.
Given:
Two dice are thrown simultaneously.
To do:
We have to find the probability of getting a sum less than 7.
Solution:
When two dice are thrown, the total possible outcomes are $6\times6=36$.
This implies,
The total number of possible outcomes $n=36$
Outcomes where we get a sum less than 7 are $[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (4, 1), (4, 2), (5, 1)]$
Total number of favourable outcomes $=15$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a sum less than 7 $=\frac{15}{36}$
$=\frac{5}{12}$
The probability of getting a sum less than 7 is $\frac{5}{12}$.
Updated on: 10-Oct-2022
87 Views
Advertisements