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In a simultaneous throw of a pair of dice, find the probability of getting a sum less than 6.
Given:
Two dice are thrown simultaneously.
To do:
We have to find the probability of getting a sum less than 6.
Solution:
When two dice are thrown, the total possible outcomes are $6\times6=36$.
This implies,
The total number of possible outcomes $n=36$
Outcomes where we get a sum less than 6 are $[(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)]$
Total number of favourable outcomes $=10$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a sum less than 6 $=\frac{10}{36}$
$=\frac{5}{18}$
The probability of getting a sum less than 6 is $\frac{5}{18}$.
Updated on: 10-Oct-2022
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