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In a simultaneous throw of a pair of dice, find the probability of getting a sum greater than 9.
Given:
Two dice are thrown simultaneously.
To do:
We have to find the probability of getting a sum greater than 9.
Solution:
When two dice are thrown, the total possible outcomes are $6\times6=36$.
This implies,
The total number of possible outcomes $n=36$
Outcomes where we get a sum greater than 9 are $[( 4,\ 6),\ ( 5,\ 5),\ ( 5,\ 6),\ ( 6,\ 4),\ ( 6,\ 5),\ ( 6,\ 6)]$
Total number of favourable outcomes $=6$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a sum greater than 9 $=\frac{6}{36}$
$=\frac{1}{6}$
The probability of getting a sum greater than 9 is $\frac{1}{6}$.
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