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In a simultaneous throw of a pair of dice, find the probability of getting a doublet of prime numbers.
Given:
Two dice are thrown simultaneously.
To do:
We have to find the probability of getting a doublet of prime numbers.
Solution:
When two dice are thrown, the total possible outcomes are $6\times6=36$.
This implies,
The total number of possible outcomes $n=36$
Outcomes where we get a doublet of prime numbers are $[( 2,\ 2),\ ( 3,\ 3),\ ( 5,\ 5)]$
Total number of favourable outcomes $=3$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a doublet of prime numbers $=\frac{3}{36}$
$=\frac{1}{12}$
The probability of getting a doublet of prime numbers is $\frac{1}{12}$.
Updated on: 10-Oct-2022
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