In a simultaneous throw of a pair of dice, find the probability of getting an even number on first.

Given:

Two dice are thrown simultaneously. 

To do:

We have to find the probability of getting an even number on first.

Solution:

When two dice are thrown, the total possible outcomes are $6\times6=36$.

This implies,

The total number of possible outcomes $n=36$

Outcomes where we get an even number on first are $[(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)]$

Total number of favourable outcomes $=18$

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability of getting an even number on first $=\frac{18}{36}$

$=\frac{1}{2}$

The probability of getting an even number on first is $\frac{1}{2}$.    

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Updated on: 10-Oct-2022

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