In a simultaneous throw of a pair of dice, find the probability of getting 5 as the sum.
Given:
Two dice are thrown simultaneously.
To do:
We have to find the probability of getting 5 as the sum.
Solution:
When two dice are thrown, the total possible outcomes are $6\times6=36$.
This implies,
The total number of possible outcomes $n=36$
Outcomes where we get 5 as the sum are $[(1, 4), (2, 3), (3, 2), (4, 1)]$
Total number of favourable outcomes $=4$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting 5 as the sum $=\frac{4}{36}$
$=\frac{1}{9}$
The probability of getting 5 as the sum is $\frac{1}{9}$.
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