Find the value of x.
$\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$

Given: $\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$

To find: We need to find the value of $\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$

Solution: 

$\frac{2x}{3} \ +\ 1\ =\ \frac{7x}{15} \ +\ 3$

$\Longrightarrow \ \ \frac{2x}{3} \ -\ \frac{7x}{15} \ =\ 2$

$\Longrightarrow \ \frac{10x}{15} \ -\ \frac{7x}{15} \ =\ 2$

$\Longrightarrow \ \frac{3x}{15} =\ 2$

$\Longrightarrow \ x\ =\ \frac{30}{3} \ =\ 10$