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Solve the expression:$x-(2x-5x-\frac{1}{3}) = x-\frac{1}{3}+\frac{1}{2}$
Given: $x-(2x-5x-\frac{1}{3}) = x-\frac{1}{3}+\frac{1}{2}$
To do: Solve the given expression
Solution:
$x-(2x-5x-\frac{1}{3}) = x-\frac{1}{3}+\frac{1}{2}$
$x - 2x +5x + \frac{1}{3} = x - \frac{1}{3} +\frac{1}{2}$
$3x=\frac{1}{2}-\frac{1}{3} -\frac{1}{3} =\frac{1}{2} -\frac{2}{3} =\frac{3 - 4}{6}$
$3x= \frac{-1}{6}$
$x = \frac{-1}{3 \times 6} = \frac{-1}{18}$
Therefore, the value of the given expression is $x=\frac{-1}{18}$
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