Solve:$ \frac{2 x}{3}+1=\frac{7 x}{15}+3 $


Given:

Given equation is \( \frac{2 x}{3}+1=\frac{7 x}{15}+3 \).

To do:

We have to find the value of $x$.

Solution:

$\frac{2 x}{3}+1=\frac{7 x}{15}+3$

$\Rightarrow \frac{2x}{3}-\frac{7x}{15}=3-1$

$\Rightarrow \frac{5\times2x-7x}{15}=2$           [LCM of 3 and 15 is 15]

$\Rightarrow \frac{10x-7x}{15}=2$

$\Rightarrow \frac{3x}{15}=2$

$\Rightarrow \frac{x}{5}=2$

$\Rightarrow x=2\times5$

$\Rightarrow x=10$

The value of $x$ is $10$.

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Updated on: 10-Oct-2022

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