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A merchant has 120 litres of oil of one kind, 180 litres of another and 240 litres of the third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?
Given: A merchant has 120 litres of oil of one kind, 180 litres of another and 240 litres of the third kind.
To find: Here we have to find the greatest capacity of the tin.
Given that the merchant wants to sell the oil by filling the three kinds of oil in tins of equal capacity.
To find the greatest capacity of such a tin we need to calculate the HCF of 120, 180 and 240.
- $180\ =\ 120\ \times\ 1\ +\ 60$
- $120\ =\ 60\ \times\ 2\ +\ 0$
- $240\ =\ 60\ \times\ 4\ +\ 0$
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