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Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.
Given :
Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively.
To find :
We have to find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.
Solution :
The highest common factor of 403, 434, 465 is the maximum capacity required.
Prime factorization of $403 = 13 \times 31$
Prime factorization of $434 = 2 \times 7 \times 31$
Prime factorization of $465 = 3 \times 5 \times 31$
HCF of 403, 434 and 465 $= 31$
Therefore, a container of 31 litres can measure the diesel of the three containers exact number of times.
Updated on: 10-Oct-2022
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