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# Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

Given :

Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively.

To find :

We have to find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

Solution :

The highest common factor of 403, 434, 465 is the maximum capacity required.

Prime factorization of $403 = 13 \times 31$

Prime factorization of $434 = 2 \times 7 \times 31$

Prime factorization of $465 = 3 \times 5 \times 31$

HCF of 403, 434 and 465 $= 31$

**Therefore, a container of 31 litres can measure the diesel of the three containers exact number of times.**

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