A body of $1\ kg$ travels a distance of 24 meters in 3.10 seconds. Assuming its speed was constant, Find its kinetic energy.

Here given, mass of the body $m=1\ kg.$

Distance travelled $s=24\ m$

Time $t=3.10\ seconds$

Therefore, velocity of the body $v=\frac{distance(s)}{time(t)}$

$=\frac{24\ m}{3.10\ seconds}$

$=7.75\ m/s$

Therefore, kinetic energy $K=\frac{1}{2}mv^2$

$=\frac{1}{2}\times1\times7.75^2$

$=30.03\ Joule$
 

Therefore, kinetic energy of the body is $30.03\ Joule$.

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Updated on: 10-Oct-2022

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