- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
A block of mass $5\ kg$ is lying on a frictionless table. A force of $20\ N$ is applied on it for $10$ seconds. Calculate its kinetic energy.
Here given, mass of the block $m=5\ kg.$, Applied force $F=20\ N$, Time $t=10\ sec.$, Initial velocity $u=0$
Let $a$ be the acceleration of the block.
Therefore, $a=\frac{F}{m}$
Or $a=\frac{20\ N}{5\ kg}$
Or $a=4\ ms^{-2}$
On using the equation of motion $v=u+at$
$v=0+4\times10$
Or $v=40\ ms^{-1}$
Therefore, Kinetic energy $K=\frac{1}{2}mv^2$
$=\frac{1}{2}\times5\times(40)^2$
$=4000\ Joule$
Advertisements