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# By how much will the speed of a body, of fixed mass, increase if its kinetic energy becomes four times its initial kinetic energy ?

As known Kinetic energy $K=\frac{1}{2}mv^2$

Where, $m\rightarrow$ mass of the body

$v\rightarrow$ velocity of the body

Here, if we double the velocity, the velocity becomes $2v$.

Then, Kinetic enrgy $K=\frac{1}{2}m( 2v)^2$

$=4\times\frac{1}{2}mv^2$

Thus, if we double the velocity then the kinetic energy will become four times.

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