If the speed of a body is halved, what will be the change in its kinetic energy?

We know the equation of the kinetic energy$K=\frac{1}{2}mv^2$

Here, $K\rightarrow$ kinetic energy of the body

$m\rightarrow$ mass of the body

$v\rightarrow$ velocity of the body
 

If the velocity of the body is halved, then it becomes $\frac{v}{2}$

Then kinetic energy of the body $K'=\frac{1}{2}m(\frac{v}{2})^2$

Or $K'=\frac{1}{4}\times\frac{1}{2}mv^2$

Or $K'=\frac{K}{4}$

Thus, when the velocity of a moving body is halved the kinetic energy becomes one-fourth of its kinetic energy.