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Found 557 Articles for Microprocessor

2K+ Views
Intel 8085 consists of a RESET_IN* pin which is an active low input pin. We RESET 8085 by placing a logic 0 on this pin at least for 0.5μs, after that the power is supplied to Vcc pin of 8085. Moreover, in practice we place the RESET_IN* in logic 0 state for a few milliseconds. A typical reset circuit which we use in ALS 8085 kit, is shown in the following Fig.The moment when the power supply is switched on, the Vcc pin gets +5V power here the RESET_IN* pin stays in logic 0 state for a time dependency on the ... Read More

986 Views
Before having a discussion regarding the demerits of I/O mapped I/O and merits of memory-mapped I/O, let us have a generic discussion regarding the difference between I/O mapped I/O and memory mapped I/O.In Memory Mapped Input Output −We allocate a memory address to an Input-Output device.Any instructions related to memory can be accessed by this Input-Output device.The Input-Output device data are also given to the Arithmetic Logical Unit.Input-Output Mapped Input Output −We give an Input-Output address to an Input-Output deviceOnly IN and OUT instructions are accessed by such devices.The ALU operations are not directly applicable to such Input-Output data.So as ... Read More

139 Views
The pins of Interrupt of 8085 are used by Input Output devices just for the initiation of the data transfer to or from 8085, without the wasting of the time of the CPU. As we have seen previously it is a very useful process when there is no well known Input Output timing characteristics, as it takes a very long time for getting ready of the device to perform the data transfer scheme. We have five interrupt pins of 8085 these are the input pins of 8085 which are named as TRAP, RST7.5, RST6.5, RST5.5 and INTR.The point to be ... Read More

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We use this method when there is a lack of accurate knowledge of the timing characteristics of the Input Output device which takes maximum time for the device to be ready for use. Suppose we resort for the checking of data transfer; the processor here wastes a huge time in the loop for the device to get ready up to the mark. For avoiding this problem, we use the interrupt-driven data transfer process. Here the processor goes ahead with its desired work, and as soon as the device is ready for data transfer process, the corresponding Input Output port sends ... Read More

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Status check data transfer process is a much more complex process than simple data transfer. We use this method is used when there is lack of accurate knowledge of the Input Output device consisting of the timing characteristics. Status information is received by the processor regarding the readiness of the Input Output device for performing the data transfer. Generally, the processor is involved in the checking of the loop for the device to get ready. The device releases from the loop when the device is ready for use for the execution of the IN or OUT instruction which depends on ... Read More

333 Views
The simplest data transfer scheme is the basic or simple data transfer. This method is beneficial to us when we have accurate knowledge of the Input-Output device timing characteristics. When we become familiar that the device is ready for transferring data, we execute the instructions IN and OUT, depending on the required data transfer direction. In this case when the Input Output port gets connected in the system as an I/O-mapped I/O port. If we connect the port as a memory-mapped I/O port, “MOV M, A”, “MOV A, M”, or any other memory reference instruction is used which depends on ... Read More

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At the time of executing one 8085 program, interruption can be done in the mid-way by the virtue of the program by an Input Output device. Interruption can be done by the method according to which the processor works, since it wants urgent communication with the processor. The data transfer schemes always want for sending information to the processor, rather receiving information from the 8085 processor. It is so because sending and receiving information in the entire 8085 data transfer scheme process plays a vital role for executing the entire program rather process.The communication is not done directly with the ... Read More

615 Views
The interrupts in 8085 is classified into the following partsThe data transfer scheme: Executing of 8085 program where the communication process is carried out systematically and is not done directly with the Input Output device. The data transfer can be either in two forms namely parallel or serial respectively.Basic or simple data transfer scheme: The simplest data transfer scheme is the basic or simple data transfer. This method is beneficial to us when we have accurate know-ledge of the Input Output device timing characteristics.Status check data transfer: Status check data transfer process is a much more complex process than simple data transfer. We ... Read More

2K+ Views
In Memory Mapped Input Output −We allocate a memory address to an Input-Output device.Any instructions related to memory can be accessed by this Input-Output device.The Input-Output device data are also given to the Arithmetic Logical Unit.Input-Output Mapped Input Output −We give an Input-Output address to an Input-Output device.Only IN and OUT instructions are accessed by such devices.The ALU operations are not directly applicable to such Input-Output data.So as a summary we can mention that −I/O is any general-purpose port used by processor/controller to handle peripherals connected to it.I/O mapped I/Os have a separate address space from the memory. So, total ... Read More

3K+ Views
In this program we will see how to find a number n from a string (an array of numbers).Problem StatementWrite 8086 Assembly language program to find a number in a string (an array of numbers). The numbers are stored at memory offset 600 onwards.DiscussionIn this program we are taking only 5 numbers. We are searching the number 25. after successful search the DX register will hold the offset address, and BX register will hold the index of that number.We are taking each number from that array and then compare it with 25. If the numbers are same, then we will ... Read More