A pair of linear equations which has a unique solution $ x=2, y=-3 $ is
(A) $ x+y=-1 $
$ 2 x-3 y=-5 $
(B) $ 2 x+5 y=-11 $
$ 4 x+10 y=-22 $
(C) $ 2 x-y=1 $
$ 3 x+2 y=0 $
(D) $ x-4 y-14=0 $
$ 5 x-y-13=0 $

AcademicMathematicsNCERTClass 10

Given:

A unique solution \( x=2, y=-3 \).

To do:

We have to find the pair of linear equations which has the unique solution \( x=2, y=-3 \).

Solution:

If $x = 2, y = - 3$ is a unique solution of any pair of equations, then these values must satisfy the pair of equations.

For option (b),       

$2x+ 5y= -11$

LHS $= 2x + 5y$

$= 2(2) + 5(-3)$

$= 4 - 15$

$= -11$

$=$ RHS

$4x + 10y = -22$

LHS $= 4x + 10y$

$= 4(2) + 10(-3)$

$= 8 - 30$

$= -22$

$=$ RHS

raja
Updated on 10-Oct-2022 13:27:13

Advertisements