Java.io.RandomAccessFile.readInt() Method

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Description

The java.io.RandomAccessFile.readInt() method reads a signed 32-bit integer from this file. This method reads 4 bytes from the file, starting at the current file pointer.

Declaration

Following is the declaration for java.io.RandomAccessFile.readInt() method

public final int readInt()

Parameters

  • NA

Return Value

This method returns the next four bytes of this file, interpreted as an int.

Exception

  • IOException -- if an I/O error occurs.

  • EOFException -- if this file reaches the end before reading four bytes.

Example

The following example shows the usage of java.io.RandomAccessFile.readInt() method.

package com.tutorialspoint;

import java.io.*;

public class RandomAccessFileDemo {

   public static void main(String[] args) {
      try {
         int i = 284;
         // create a new RandomAccessFile with filename test
         RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw");

         // write something in the file
         raf.writeInt(123);

         // set the file pointer at 0 position
         raf.seek(0);

         // print the int
         System.out.println("" + raf.readInt());

         // set the file pointer at 0 position
         raf.seek(0);

         // write something in the file
         raf.writeInt(i);

         // set the file pointer at 0 position
         raf.seek(0);

         // print the int
         System.out.println("" + raf.readInt());
      } catch (IOException ex) {
         ex.printStackTrace();
      }


   }
}

Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program:

ABCDE  

Let us compile and run the above program, this will produce the following result:

123
284



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