Java.io.RandomAccessFile.readFloat() Method

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Description

The java.io.RandomAccessFile.readFloat() method Reads a float from this file. This method reads an int value, starting at the current file pointer, as if by the readInt method and then converts that int to a float using the intBitsToFloat method in class Float.

Declaration

Following is the declaration for java.io.RandomAccessFile.readFloat() method.

public final float readFloat()

Parameters

NA

Return Value

This method returns the next four bytes of this file, interpreted as a float.

Exception

• IOException − If an I/O error occurs.Not thrown if end-of-file has been reached.

• EOFException − If this file reaches the end before reading four bytes.

Example

The following example shows the usage of java.io.RandomAccessFile.readFloat() method.

package com.tutorialspoint;

import java.io.*;

public class RandomAccessFileDemo {
   public static void main(String[] args) {

      try {
         float f = 1234.56f;
         
         // create a new RandomAccessFile with filename test
         RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw");

         // write something in the file
         raf.writeFloat(986.543f);

         // set the file pointer at 0 position
         raf.seek(0);

         // read float
         System.out.println("" + raf.readFloat());

         // set the file pointer at 0 position
         raf.seek(0);

         // write a float
         raf.writeFloat(f);

         // set the file pointer at 0 position
         raf.seek(0);

         // read float
         System.out.println("" + raf.readFloat());
      } catch (IOException ex) {
         ex.printStackTrace();
      }
   }
}

Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −

ABCDE  

Let us compile and run the above program, this will produce the following result −

986.543
1234.56