Java.io.RandomAccessFile.readFloat() Method

Description

The java.io.RandomAccessFile.readFloat() method Reads a float from this file. This method reads an int value, starting at the current file pointer, as if by the readInt method and then converts that int to a float using the intBitsToFloat method in class Float.

Declaration

Following is the declaration for java.io.RandomAccessFile.readFloat() method

public final float readFloat()

Parameters

• NA

Return Value

This method returns the next four bytes of this file, interpreted as a float.

Exception

• IOException -- if an I/O error occurs.Not thrown if end-of-file has been reached.

• EOFException -- if this file reaches the end before reading four bytes.

Example

The following example shows the usage of java.io.RandomAccessFile.readFloat() method.

package com.tutorialspoint;

import java.io.*;

public class RandomAccessFileDemo {

   public static void main(String[] args) {
      try {
         float f = 1234.56f;
         // create a new RandomAccessFile with filename test
         RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw");

         // write something in the file
         raf.writeFloat(986.543f);

         // set the file pointer at 0 position
         raf.seek(0);

         // read float
         System.out.println("" + raf.readFloat());

         // set the file pointer at 0 position
         raf.seek(0);

         // write a float
         raf.writeFloat(f);

         // set the file pointer at 0 position
         raf.seek(0);

         // read float
         System.out.println("" + raf.readFloat());
      } catch (IOException ex) {
         ex.printStackTrace();
      }

   }
}

Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program:

ABCDE  

Let us compile and run the above program, this will produce the following result:

986.543
1234.56