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# The length and breadth of three rectangles are as given below :

**(a)** $ 9 \mathrm{~m} $ and $ 6 \mathrm{~m} $

**(b) $ 17 \mathrm{~m} $ and $ 3 \mathrm{~m} $**

**(c) $ 4 \mathrm{~m} $ and $ 14 \mathrm{~m} $**

Which one has the largest area and which one has the smallest?

**(c) $ 4 \mathrm{~m} $ and $ 14 \mathrm{~m} $**

Which one has the largest area and which one has the smallest?

Which one has the largest area and which one has the smallest?

**Given:**

The length and breadth of three rectangles are:

(a) $9\ m$ and $6\ m$

(b) $17\ m$ and $3\ m$

(c) $4\ m$ and $14\ m$.**
**

**To do:**

We have to find which rectangle has the largest area and which rectangle has the smallest area.

**Solution:**

We know that,

The area of a rectangle with length '$l$' and breadth '$b$' is $l \times b$.

Therefore,

(a) Here,

Length $l =9\ m$

Breadth $b =6\ m$

The area of the rectangle $ = 9\ m\times6\ m$

$=54\ m^2$

(b) Here,

Length $l =17\ m$

Breadth $b =3\ m$

The area of the rectangle $ = 17\ m\times3\ m$

$=51\ m^2$

(c) Here,

Length $l =14\ m$

Breadth $b =4\ m$

The area of the rectangle $ = 14\ m\times4\ m$

$=56\ m^2$

The rectangle with an area of $56\ m^2$ is the largest one and the rectangle with an area of $51\ m^2$ is the smallest one.

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