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The length and breadth of three rectangles are as given below :
(a) $ 9 \mathrm{~m} $ and $ 6 \mathrm{~m} $
(b) $ 17 \mathrm{~m} $ and $ 3 \mathrm{~m} $
(c) $ 4 \mathrm{~m} $ and $ 14 \mathrm{~m} $
Which one has the largest area and which one has the smallest?
Given:
The length and breadth of three rectangles are:
(a) $9\ m$ and $6\ m$
(b) $17\ m$ and $3\ m$
(c) $4\ m$ and $14\ m$.
To do:
We have to find which rectangle has the largest area and which rectangle has the smallest area.
Solution:
We know that,
The area of a rectangle with length '$l$' and breadth '$b$' is $l \times b$.
Therefore,
(a) Here,
Length $l =9\ m$
Breadth $b =6\ m$
The area of the rectangle $ = 9\ m\times6\ m$
$=54\ m^2$
(b) Here,
Length $l =17\ m$
Breadth $b =3\ m$
The area of the rectangle $ = 17\ m\times3\ m$
$=51\ m^2$
(c) Here,
Length $l =14\ m$
Breadth $b =4\ m$
The area of the rectangle $ = 14\ m\times4\ m$
$=56\ m^2$
The rectangle with an area of $56\ m^2$ is the largest one and the rectangle with an area of $51\ m^2$ is the smallest one.
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