# The length and breadth of three rectangles are as given below :(a) $9 \mathrm{~m}$ and $6 \mathrm{~m}$(b) $17 \mathrm{~m}$ and $3 \mathrm{~m}$(c) $4 \mathrm{~m}$ and $14 \mathrm{~m}$Which one has the largest area and which one has the smallest?

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Given:

The length and breadth of three rectangles are:

(a) $9\ m$ and $6\ m$

(b) $17\ m$ and $3\ m$

(c) $4\ m$ and $14\ m$.

To do:

We have to find which rectangle has the largest area and which rectangle has the smallest area.

Solution:

We know that,

The area of a rectangle with length '$l$' and breadth '$b$' is $l \times b$.

Therefore,

(a) Here,

Length $l =9\ m$

Breadth $b =6\ m$

The area of the rectangle $= 9\ m\times6\ m$

$=54\ m^2$

(b) Here,

Length $l =17\ m$

Breadth $b =3\ m$

The area of the rectangle $= 17\ m\times3\ m$

$=51\ m^2$

(c) Here,

Length $l =14\ m$

Breadth $b =4\ m$

The area of the rectangle $= 14\ m\times4\ m$

$=56\ m^2$

The rectangle with an area of $56\ m^2$ is the largest one and the rectangle with an area of $51\ m^2$ is the smallest one.

Updated on 10-Oct-2022 13:36:29