A godown measures $ 40 \mathrm{~m} \times 25 \mathrm{~m} \times 15 \mathrm{~m} $. Find the maximum number of wooden crates each measuring $ 1.5 \mathrm{~m} \times 1.25 \mathrm{~m} \times 0.5 \mathrm{~m} $ that can be stored in the godown.
Given:
A godown measures $40\ m \times 25\ m \times 10\ m$.
To do:
We have to find the maximum number of wooden crates each measuring $1.5\ m \times 1.25\ m \times 0.5\ m$ that can be stored in the godown.
Solution:
Length of the godown $(L) = 40\ m$
Breadth of the godown $(B) = 25\ m$
Height of the godown $(H) = 10\ m$
Therefore,
Volume of the godown $= LBH$
$= 40 \times 25 \times 10$
$= 10000\ m^3$
Dimensions of each wooden crate $= 1.5\ m \times 1.25\ m \times 0.5\ m$
Volume of each crate $= 1.5 \times 1.25 \times 0.5$
$= 0.9375\ m^3$
This implies,
The number of crates to be stored in the godown $=\frac{\text { Volume of godown }}{\text { Volume of one crate }}$
$=\frac{10000}{0.9375}$
$=\frac{10000 \times 10000}{9375}$
$=10666$ crates
The maximum number of wooden crates each measuring $1.5\ m \times 1.25\ m \times 0.5\ m$ that can be stored in the godown is 10666 crates.
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