# Find the areas of the rectangles whose sides are :(a) $3 \mathrm{~cm}$ and $4 \mathrm{~cm}$(b) $12 \mathrm{~m}$ and $21 \mathrm{~m}$(c) $2 \mathrm{~km}$ and $3 \mathrm{~km}$(d) $2 \mathrm{~m}$ and $70 \mathrm{~cm}$

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To do:

We have to find the areas of the rectangles whose sides are: (a) $3 \ cm$ and $4\ cm$ (b) $12\ m$ and $21\ m$ (c) $2\ km$ and $3\ km$ (d) $2\ m$ and $70\ cm$.

Solution:

We know that,

The area of a rectangle with length '$l$' and breadth '$b$' is $l \times b$.

Therefore,

(a) Here,

Length $l =4\ cm$

Breadth $b =3\ cm$

The area of the rectangle $= 4\ cm\times3\ cm$

$=12\ cm^2$

(b) Here,

Length $l =21\ m$

Breadth $b =12\ m$

The area of the rectangle $= 21\ m\times12\ m$

$=252\ m^2$

(c) Here,

Length $l =3\ km$

Breadth $b =2\ km$

The area of the rectangle $= 3\ km\times2\ km$

$=6\ km^2$

(d) $1\ m=100\ cm$

This implies,

$1\ cm=\frac{1}{100}\ m$

$=\frac{70}{100}\ m$

$= 0.7\ m$

Here,

Length $l =2\ m$

Breadth $b =0.7\ m$

The area of the rectangle $= 2\ m\times0.7\ cm$

$=1.4\ m^2$

Updated on 10-Oct-2022 13:36:29