Write in decimal form, and find the quotient and the remainder.
a) $ 4 \mathrm{~kg} 14 \mathrm{~g} \div 6 $
b) $ 23 \mathrm{~km} 72 \mathrm{~m} \div 10 $

Given:

a) \( 4 \mathrm{~kg} 14 \mathrm{~g} \div 6 \)
b) \( 23 \mathrm{~km} 72 \mathrm{~m} \div 10 \)

To do:

We have to write the given expressions in decimal form and find the quotient and the remainder.
Solution:
(a) We know that,

$1\ kg=1000\ g$ 

This implies,

$4\ kg\ 14\ g=4\times1000+14\ g$

$=4000+14\ g$

$=4014\ g$

$4 \mathrm{~kg} 14 \mathrm{~g} \div 6=4014\div 6\ g$

$=\frac{4014}{6}\ g$

$=669\ g$

Quotient $=669$ and Remainder $=0$

(b) We know that,

$1\ km=1000\ m$ 

This implies,

$23\ km\ 72\ m=23\times1000+72\ m$

$=23000+72\ m$

$=23072\ m$

$23 \mathrm{~km} 72 \mathrm{~m} \div 10=23072\div 10\ m$

$=\frac{23072}{10}\ m$

$=2307\times10+2\ m$

Quotient $=2307$ and Remainder $=2$

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Updated on: 10-Oct-2022

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