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# Surface Area of 3D Shapes in Python

Suppose there is a N x N grid, we place some 1 x 1 x 1 cubes. in it. Now for each value v = grid[i][j] represents a tower of v cubes placed on top of grid cell(i, j). We have to find the total surface area of the resulting shapes.

So, if the input is like [[1,2],[3,4]], then the output will be 34.

To solve this, we will follow these steps −

- Define a function adjacentArea(). This will take row
- area := 0
- for i in range 0 to size of row - 1, do
- if row[i] and row[i + 1] is non-zero, then
- area := area + 2 * minimum of row[i], row[i+1]

- if row[i] and row[i + 1] is non-zero, then
- return area
- From the main method do the following −
- z := 2* (sum of (sum of value i in row) for all row in grid)
- x_plus_y := sum of all elements in the grid * 4
- x_adjacent := sum of adjacentArea(row) for all row in grid
- y_adjacent := sum of adjacentArea(row) for all column in the grid
- return z +(x_plus_y - x_adjacent - y_adjacent)

Let us see the following implementation to get better understanding −

## Example

class Solution: def surfaceArea(self, grid): def adjacentArea(row): area = 0 for i in range(len(row) - 1): if row[i] and row[i + 1]: area += 2 * min(row[i], row[i+1]) return area z = sum([sum(i > 0 for i in row) for row in grid]) * 2 x_plus_y = sum([sum(row) for row in grid]) * 4 x_adjacent = sum([adjacentArea(row) for row in grid]) y_adjacent = sum([adjacentArea(row) for row in zip(*grid)]) return z + (x_plus_y - x_adjacent - y_adjacent) ob = Solution() print(ob.surfaceArea([[1,2],[3,4]]))

## Input

[[1,2],[3,4]]

## Output

34

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