Write the first five terms of each of the following sequences whose nth terms are:
$ a_{n}=\frac{n-2}{3} $

Given:

\( a_{n}=\frac{n-2}{3} \)

To do:

We have to find the first five terms of the given sequence.

Solution:

$a_n=\frac{n-2}{3}$

Taking $n=1$, we get

$a_1=\frac{1-2}{3}=\frac{-1}{3}$

Taking $n=2$, we get

$a_2=\frac{2-2}{3}=\frac{0}{3}=0$

Taking $n=3$, we get

$a_3=\frac{3-2}{3}=\frac{1}{3}$

Taking $n=4$, we get

$a_4=\frac{4-2}{3}=\frac{2}{3}$

Taking $n=5$, we get

$a_5=\frac{5-2}{3}=\frac{3}{3}=1$

Hence, the first five terms of the given sequence are $\frac{-1}{3}, 0, \frac{1}{3}, \frac{2}{3}$ and $1$. 

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

26 Views

Kickstart Your Career

Get certified by completing the course

Get Started