Write the first five terms of each of the following sequences whose nth terms are:
$ a_{n}=3 n+2 $

Given:

\( a_{n}=3 n+2 \)

To do:

We have to find the first five terms of the given sequence.

Solution:

$a_n=3n+2$

Taking $n=1$, we get

$a_1=3(1)+2=3+2=5$

Taking $n=2$, we get

$a_2=3(2)+2=6+2=8$

Taking $n=3$, we get

$a_3=3(3)+2=9+2=11$

Taking $n=4$, we get

$a_4=3(4)+2=12+2=14$

Taking $n=5$, we get

$a_5=3(5)+2=15+2=17$

Hence, the first five terms of the given sequence are $5, 8, 11, 14$ and $17$.

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Updated on: 10-Oct-2022

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