Find the next five terms of each of the following sequences given by :
$ a_{1}=a_{2}=2, a_{n}=a_{n-1}-3, n>2 $
Given:
\( a_{1}=a_{2}=2, a_{n}=a_{n-1}-3, n>2 \)
To do:
We have to find the next five terms of the given sequence.
Solution:
The next five terms in the sequence are obtained by substituting $n=3, 4, 5, 6, 7$ respectively.
When $n=3$,
$a_3=a_{3-1}-3$
$=a_2-3$
$=2-3$
$=-1$
When $n=4$,
$a_4=a_{4-1}-3$
$=a_3-3$
$=-1-3$
$=-4$
When $n=5$,
$a_5=a_{5-1}-3$
$=a_4-3$
$=-4-3$
$=-7$
When $n=6$,
$a_6=a_{6-1}-3$
$=a_5-3$
$=-7-3$
$=-10$
When $n=7$,
$a_7=a_{7-1}-3$
$=a_6-3$
$=-10-3$
$=-13$
Therefore, the next five terms of the given sequence are $-1, -4, -7, -10$ and $-13$.
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