Write the first five terms of each of the following sequences whose nth terms are:
$ a_{n}=\frac{3 n-2}{5} $

Given:

\( a_{n}=\frac{3 n-2}{5} \)

To do:

We have to find the first five terms of the given sequence.

Solution:

$a_n=\frac{3n-2}{5}$

Taking $n=1$, we get

$a_1=\frac{3(1)-2}{5}=\frac{3-2}{5}=\frac{1}{5}$

Taking $n=2$, we get

$a_2=\frac{3(2)-2}{5}=\frac{6-2}{5}=\frac{4}{5}$

Taking $n=3$, we get

$a_3=\frac{3(3)-2}{5}=\frac{9-2}{5}=\frac{7}{5}$

Taking $n=4$, we get

$a_4=\frac{3(4)-2}{5}=\frac{12-2}{5}=\frac{10}{5}=2$

Taking $n=5$, we get

$a_5=\frac{3(5)-2}{5}=\frac{15-2}{5}=\frac{13}{5}$

Hence, the first five terms of the given sequence are $\frac{1}{5}, \frac{4}{5}, \frac{7}{5}, 2$ and $\frac{13}{5}$.  

Tutorialspoint

e

Updated on: 10-Oct-2022

28 Views

Kickstart Your Career

Get certified by completing the course

Get Started