Find the indicated terms in each of the following sequences whose nth terms are:
$ a_{n}=n(n-1)(n-2) ; a_{5} $ and $ a_{8} $
Given:
$a_{n}=n(n-1)(n-2)$
To do:
We have to find $a_{5}$ and $a_{8}$.
Solution:
To find $a_{5}$, we have to substitute $5$ in place of $n$ in $a_{n}=n(n-1)(n-2)$.
This implies,
$a_{5}=5(5-1)(5-2)$
$=5(4)(3)$
$=60$.
To find $a_{8}$, we have to substitute $8$ in place of $n$ in $a_{n}=n(n-1)(n-2)$.
This implies,
$a_{8}=8(8-1)(8-2)$
$=8(7)(6)$
$=336$.
Therefore, $a_{5}=60$ and $a_{8}=336$.
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