Which of the two rational numbers is greater in the given pair?
1) $\frac{3}{8}$ or 0
2) $\frac{-2}{9}$ or 0
Given:
i) $\frac{3}{8} $ or 0.
ii) $\frac{-2}{9} $ or 0.
To find: We have to find which is greater among the two numbers.
Solution:
1) $\frac{3}{8} $ or 0.
Obviously $\frac{3}{8}$ [a positive rational number] > 0 or $\frac{0}{8}$, a rational number too.
As 3 > 0, $\frac{3}{8} > \frac{0}{8}$ or $\frac{3}{8} > 0 $ as $\frac{0}{8}$ = 0
2) $\frac{-2}{9} $ or 0.
Obviously $\frac{-2}{9}$ [a negative rational number] < 0 or $\frac{0}{9}$, a rational number too.
As - 2 < 0, $\frac{-2}{9} < \frac{0}{9}$ or $\frac{-2}{9}$ < 0 as $\frac{0}{9} = 0$
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