The product of two rational numbers is $\frac{-8}{9}$ if one of the numbers is $\frac{-4}{15}$, find other.

Given:

The product of two rational numbers is $\frac{-8}{9}$.

One of the numbers is $\frac{-4}{15}$.

To do:

We have to find the other number.

Solution:

Let the other number be $x$.

This implies,

$\frac{-4}{15}\times x=\frac{-8}{9}$

$x=\frac{-8}{9}\div\frac{-4}{15}$

$x=\frac{-8}{9}\times\frac{15}{-4}$

$x=\frac{-8\times15}{9\times-4}$

$x=\frac{2\times5}{3\times1}$

$x=\frac{10}{3}$

Therefore, the other number is $\frac{10}{3}$.    

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Updated on: 10-Oct-2022

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