Is $ \frac{8}{9} $ the multiplicative inverse of $ -1 \frac{1}{8} $ ? Why or why not?
To do:
We have to find whether \( \frac{8}{9} \) is the multiplicative inverse of \( -1 \frac{1}{8} \).
Solution:
$-1\frac{1}{8} =-(1\frac{1}{8})$
$=-(\frac{1\times8+1}{8})$
$=-\frac{9}{8}$
We know that,
The multiplicative inverse of $\frac{a}{b}$ is $\frac{b}{a}$
Therefore,
The multiplicative inverse of $\frac{-9}{8}$ is $\frac{8}{-9}=\frac{-8}{9}$
$\frac{-8}{9}≠\frac{8}{9}$
Hence, $\frac{8}{9}$ is not the multiplicative inverse of $-1\frac{1}{8}$.
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