Compare the following numbers: $( 1)\ -7,\ -2$$( 2).\ 0, \frac{-9}{5}$$(3)\ \frac{8}{7}, 0$

Given: $( 1)\ -7,\ -2$

$( 2).\ 0, \frac{-9}{5}$

$(3)\ \frac{8}{7}, 0$

To do: To compare the given number.

Solution:

$( 1).\ -7,\ -2$

Given numbers are $-7$ and $-2$

$\because -2$ has more value than $-7$

$\therefore -7<-2$

$( 2).\ 0, \frac{-9}{5}$

$\because 0$ is always greater than all negative integers.

$\therefore \frac{-9}{5}<0$

$(3).\ \frac{8}{7}, 0$

$\because 0$ is always less than all positive integers.

$\therefore 0<\frac{8}{7}$

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Updated on: 10-Oct-2022

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