The area of a rhombus is $72\ cm^ 2$ . If its perimeter is $36\ cm$, then find its altitude.

Given: The area of a rhombus is $72\ cm^ 2$ . If its perimeter is $36\ cm$.

To do: To find its altitude. 

Solution:

The area of a rhombus$=72\ cm^2$

The perimeter of a rhombus$=36\ cm$

To find, the altitude of a rhombus $( h)=?$

As known that,

The perimeter of a rhombus$=4\times Side( a)$

$\Rightarrow 4 × Side( a)=36\ cm$

$\Rightarrow a=\frac{36}{4}=9\ cm$

$\therefore$ The base of rhombus$=9\ cm$

The area of a rhombus$=Base\times altitude$

$\Rightarrow 9\ cm\times h=72$ 

$\Rightarrow h=8\ cm$

Thus, the altitude of a rhombus $( h)=8\ cm$