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# The area of a rhombus is $72\ cm^2$ . If its perimeter is $32\ cm$, find its altitude.

**Given:**The area of a rhombus is $72\ cm^2$ . If its perimeter is $32\ cm$

**To do:**To find its altitude.

**Solution:**

The area of a rhombus$=72\ cm^2$

The perimeter of a rhombus$=32\ cm$

To find, the altitude of a rhombus $( h)=?$

As known that,

The perimeter of a rhombus$=4\times Side( a)$

$\Rightarrow 4 × Side( a)=32\ cm$

$\Rightarrow a=\frac{36}{4}=8\ cm$

$\therefore$ The base of rhombus$=8\ cm$

The area of a rhombus$=Base\times altitude$

$\Rightarrow 8\ cm\times h=72$

$\Rightarrow h=\frac{72}{8}=9\ cm$

Thus, the altitude of a rhombus $( h)=9\ cm$

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