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The area of a rhombus is $72\ cm^2$ . If its perimeter is $32\ cm$, find its altitude.
Given: The area of a rhombus is $72\ cm^2$ . If its perimeter is $32\ cm$
To do: To find its altitude.
Solution:
The area of a rhombus$=72\ cm^2$
The perimeter of a rhombus$=32\ cm$
To find, the altitude of a rhombus $( h)=?$
As known that,
The perimeter of a rhombus$=4\times Side( a)$
$\Rightarrow 4 × Side( a)=32\ cm$
$\Rightarrow a=\frac{36}{4}=8\ cm$
$\therefore$ The base of rhombus$=8\ cm$
The area of a rhombus$=Base\times altitude$
$\Rightarrow 8\ cm\times h=72$
$\Rightarrow h=\frac{72}{8}=9\ cm$
Thus, the altitude of a rhombus $( h)=9\ cm$
Updated on: 10-Oct-2022
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