- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

# The area of a rhombus is $384\ m^2$ and one of its diagonals is $24\ m$. What is the perimeter of the rhombus?

**Given: **

The area of a rhombus is $384\ m^2$ and one of its diagonals is $24\ m$.

**To do: **

We have to find the perimeter of the rhombus.

**Solution:**

Let $d_1$ and $d_2$ be the two diagonals of a rhombus.

Then, $d_1=24\ m$

We know that,

Area of Rhombus $=\frac{d_1\times d_2}{2}$

$384=\frac{(24)(d_2)}{2}$

$d_2=32$

Side of the rhombus $s=\sqrt{(\frac{d_1}{2})^2+(\frac{d_2}{2})^2}$

$=\sqrt{(\frac{24}{2})^2+(\frac{32}{2})^2}$

$=\sqrt{(12)^2+(16)^2}$

$=\sqrt{144+256}$

$=\sqrt{400}$

$=20\ m$

Perimeter $=4\times s$

$=4\times20\ m$

$=80\ m$

**The perimeter of the rhombus is 84 m.**

Advertisements