Find the Perimeter of a Rhombus whose diagonals measure 24 cm and 32 cm.

Given :

The measure of the diagonals of the rhombus are 24 cm and 32 cm.

Let p = 24 cm and q = 32 cm.

To find :

We have o find the Perimeter of Rhombus

Solution :

We know that,

The perimeter of a rhombus whose diagonals measure p units and q units is $2\sqrt{p^{2} +q^{2}} \ units$.

The perimeter of the given rhombus $= 2\sqrt{24^{2} +32^{2}} \ cm$

                                                                   $=2\sqrt{576+1024} \ cm$

                                                                   $=2\sqrt{1600} \ cm$

                                                                   $=2\times40$ cm

                                                                   $=80$ cm

The perimeter of the given rhombus is 80 cm.

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Updated on: 10-Oct-2022

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