Find the area of a rhombus whose diagonals are:$16\ cm$ and $24\ cm $.

Given: A rhombus whose diagonals are $16\ cm$ and $24\ cm$.

To do: To find the area of the rhombus.

Solution:

As given,

Diagonals of the rhombus are $d_1=16\ cm$ and $d_2=24\ cm$

$\therefore$ Area of the rhombus$=\frac{1}{2}\times d_1\times d_2$

$=\frac{1}{2}\times16\times24$

$=8\times 24$

$=192\ cm^2$

Thus, the area of the rhombus is $192\ cm^2$.